Answer:
Its b!!!!!!
Step-by-step explanation:
The answer is 1/12 but i need 20 characters so jsnsnjdjdndjdjdj
F(x)=4x+1
g(x)=x^2-5
(f . g)(x)=?
(f . g)(x) = f(x) . g(x) = (4x+1).(x^2-5)=(4x).(x^2)+(4x).(-5)+(1).(x^2)+(1).(-5)
(f . g)(x) = 4x^(1+2)-20x+x^2-5
(f . g)(x)=4x^3+x^2-20x-5
Answer: Option A. 4x^3+x^2-20x-5
Given the markup of 75%, the selling price of the item became:
Cost×(1+Markup)=selling price
the initial price of the house will therefore be:
C×(1+0.75)=350
1.75C=350
C=350/1.75
C=$200
therefore the initial selling price was $200. Given that after the markup price was later reduced by 20%, the new price became:
80/100×350
=$280
If the price was later reduced by 30% the new price was:
70/100×280
=$196
From this final price we see that if the original price was $200 and the selling price is now $196, then the item is actually selling at lose.<span />
Answer: a=51
Step-by-step explanation: