Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
Answer:
48,000
Step-by-step explanation:
3,000 x 2 = 6000 (decade one)
6000 x 2 = 12000 (decade two)
12000 x 2 = 24000 (decade three)
24000 x 2 = 48000 (decade four)
Answer:
c=15
Step-by-step explanation:
5 dogs --------- 3 cats
25 dogs---------c cats
c=(25x3)/5
=75/5
=15 cats
The computation shows that the values of Δy and dy will be 0.572 and 0.4 respectively.
<h3>How to compute the values?</h3>
The value of Δy will be computed thus:
Δy = y(x + Δx) - y(x)
= y(1.1) - y(1)
= 0.5(1.1)⁸ - 0.5(1)⁸
= 0.572
The value of dy will be:
= y'(x)dx
= (0.5)⁸ × x⁷(0.1)
= 0.4 (1)⁷
= 0.4
Learn more about finding values on:
brainly.com/question/25927269
The two fractions are equivalent as if you simplify 80/100 by dividing the top and bottom by 10 you get 8/10
Hope this helped :)