An acid can be defined as a proton donor.
I think question 1 is B
And question 2 is also B
The molarity of the solution is equal to 0.500M.
<h3>Mole calculation</h3>
To calculate the molarity of a solution, one must use the value of the amount of moles and the volume, so that:
![M = \frac{mol}{v}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7Bmol%7D%7Bv%7D)
So, applying the values given in the question we have:
![M = \frac{1mol}{2L}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B1mol%7D%7B2L%7D)
![M = 0.5mol/L](https://tex.z-dn.net/?f=M%20%3D%200.5mol%2FL)
So, the molarity of the solution is equal to 0.500M.
Learn more about mole calculation in: brainly.com/question/2845237
C = 1.14 M , T = 10 + 273.15 = 283.15 K salt concentration = 176 mg /L NaCl
π total = CRT = 1.14 x 0.0821 x 283.15 = 26.5 atm
mass of NaCl = 176 mg = 0.176 g
Molarity =
![\frac{0.176}{57.96} x \frac{1}{1L} = 3.0366 x 10^{-3} M](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.176%7D%7B57.96%7D%20x%20%20%5Cfrac%7B1%7D%7B1L%7D%20%20%3D%203.0366%20x%2010%5E%7B-3%7D%20M%20%20)
maximum concentration allowed C = 3.0366 x 10⁻³ M
π max. conc. = 2 x 3.0366 x 10⁻³ x 0.0821 x 283.15 = 0.141 atm
π external = π total - π max. conc.
= 26.5 - 0.141 = 26.3 atm
Answer:
n = 1.24 moles
Explanation:
Given that,
Mass = 153 grams
Molar mass of KClO₃ = 122.55 g/mol
We need to find the number of moles.
We know that,
No. of moles = given mass/molar mass
So,
![n=\dfrac{153}{122.55 }\\\\n=1.24](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B153%7D%7B122.55%20%7D%5C%5C%5C%5Cn%3D1.24)
So, there are 1.24 moles in 153 g of KClO₃.