Answer:
Exit velocity of air is 96.43 m/s.
Explanation:
Given that
For air
Now from first law of thermodynamics for open system at steady state
For diffuser
We know that
So the exit velocity of air is 96.43 m/s.
Answer is: freezing point is -0,226°C.
Answer is: the molal concentration of glucose in this solution is 1,478 m.
m(KCl) = 15 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 15 g ÷ 74,55 g/mol.
n(KCl) = 0,2 mol
m(H₂O) = 1650 g ÷ 1000 g/kg = 1,65 kg.
b = n(KCl) ÷ m(H₂O).
b = 0,2 mol ÷ 1,65 kg = 0,122 m.
Kf(water) = 1,86°C/m.
ΔT = Kf(water) · b(solution).
ΔT = 1,86°C/m · 0,122 m.
ΔT = 0,226°C.
The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
Answer:
Element Y, or the third option
Explanation:
Alkanes are insoluble in water, but soluble in ether. Their boiling points are pretty low, barely reaching 200 degrees, so element Y is an alkane.
