Answer:
Option A; V = 2.92 L
Explanation:
If we assume a lot of things, like:
The gas is an ideal gas.
The temperature is constant.
The gas does not interchange mass with the environment.
Then we have the relation:
P*V = n*R*T = constant.
Where:
P = pressure
V = volume
n = number of moles
R = constant of the ideal gas
T = temperature.
We know that when P = 0.55 atm, the volume is 5.31 L
Then:
(0.55 atm)*(5.31 L) = constant
Now, when the gas is at standard pressure ( P = 1 atm)
We still have the relation:
P*V = constant = (0.55 atm)*(5.31 L)
(1 atm)*V = (0.55 atm)*(5.31 L)
Now we only need to solve this for V.
V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L
V = 2.92 L
Then the correct option is A.
Na⁺¹₃P⁺⁵O⁻²₄
+1*3 + (+5) + (-2*4) = 0
Answer:
375 mL
Explanation:
M1*V1 = M2*V2
M1 = 1.00 M
V1 = ?
M2 = 0.750 M
V2 = 0.500 L
1.00 M * V1 = 0.750 M * 0.500 L
V1 = 0.750*0.500/1.00 = 0.375 L = 375 mL
Three groups
gases, metals, metalliods/nonmetals
