Allison car can drive 450 miles on just 12 gallons of gas what is the mileage per gallon

A line passes through the points (1, 4) and (3, 4). Which is the equation of the line?

xeze [42]

Answer:

y = -4x + 8

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step 1: Find slope m

$m=\frac{-4-4}{3-1}$

$m=\frac{-8}{2}$

m = -4

y = -4x + b

Step 2: Find y-intercept b

4 = -4(1) + b

4 = -4 + b

8 = b

Step 3: Rewrite linear equation

y = -4x + 8

8 0

3 years ago

Find the value of: a) 5x when x = 6 B) 3y when y = -7

Y_Kistochka [10]

Answer:

a 30 b -21

Step-by-step explanation:

a 5x = 5(6)

= 30

b 3y = 3(-7)

= -21

7 0

3 years ago

Read 2 more answers

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

The population of current statistics students has ages with mean mu and standard deviation sigma. samples of statistics students

hram777 [196]

Answer: The central limit theorem tells us that when random samples are chosen the results tend to approach a normal distribution.

The basic idea is that the more random samples that you select, the closer you should get to the mean. In most cases, 30 or more samples is regarded as a large enough sample to get close to the mean. Our sample is 48, so we should be close to the mean.

3 0

3 years ago

64 percent of what number is 48

sergey [27]

The answer I got was 75%

5 0

3 years ago