All categories

4 years ago

What is a possible reason that ecosystem 2 has fewer species than ecosystem 1?

Chemistry

1 answer:

olganol [36]4 years ago

7 0

it doesn't repopulate as fast because ecosystem 2 could have more trouble reproducing then ecosystem 1.

You might be interested in

Determine the number o( bonding electrons and the number of nonbonding electrons in the structure of CO_2. Enter the number of b

Rom4ik [11]

NOF (6,12)

CO2 (8,8)

BeF (4,12)

7 0

3 years ago

What is the percent by volume of ethanol (C2H60, or ethyl alcohol) in the final solution when 90 mL of ethanol is diluted to a v

r-ruslan [8.4K]

Answer:

16.0%.

Explanation:

Volume percent of a substance is the ratio of the substance volume to the solution volume multiplied by 100.

V % of ethanol = (volume of ethanol / volume of the solution) x 100.

volume of ethanol = 90.0 mL, volume of the solution = 550.0 mL.

∴ V % of ethanol = (90.0 mL / 550.0 mL) x 100 = 16.36% ≅ 16.0%.

8 0

3 years ago

Solid chromium (III) reacts with oxygen gas to form solid Cr2O3. What is this type of reaction?

mafiozo [28]

Answer:

.081 g of O2

Explanation:

4Cr + 3O2 -----> 2Cr2O3

.175 g Cr x [1 mole / 52.0 g] x [2 moles Cr2O3 / 4 moles Cr] x [152 g / 1 mole] = .256 g of Cr2O3

.175 g Cr x [1 mole / 52.0 g] x [3 moles O2 / 4 moles Cr] x [32 g / 1 mole] = .081 g of O2

5 0

3 years ago

2 HCN + _ CuSO4 + H2SO4 + Cu(CN)2<br><br> Reaction type?

HACTEHA [7]

This is a double replacement or double displacement reaction

3 0

3 years ago

Part A How much time (in minutes) will it take for the water heater to heat the 5.5 L of water from 23 ∘C to 43 ∘C? (Assume that

harina [27]

Answer:

Time = t = 30.01 minutes

Explanation:

The missing part of the question is that "The water heater power rating is 255 Watts, where 1 Watt = 1 J/s.

Firstly, calculating the work done by water heater to heat 5.5 L of water from 23° C to 43°C.

Work Done = Q = m C ΔT

where,

Q = Heat Transfer

m = mass of water

m = Density x Volume = 1 g/mL x 5.5 L = 1000g/L x 5.5L = 5500 g

ΔT = Temperature Difference = 43-23 = 20°C

C = Heat Capacity of Water = 4.186 J/g °C

Therefore,

$Q = (5500g)(4.186J/gC) (20C)\\Q = 460460 J$

Since, Power can be given as Work done per unit time,

$P = \frac{W}{t}$

or, in this case,

$P = \frac{Q}{t}\\$

Here,

P = 255W or P = 255J (Since 1W = 1J)

$P=\frac{Q}{t}\\255 = \frac{460460}{t}\\t = \frac{460460}{255}\\t = 1805.72 s\\t = \frac{1805.72}{60}\\t = 30.01 min$

3 0

3 years ago