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Thepotemich [5.8K]
3 years ago
15

What volume is equal to 12.0m3

Chemistry
2 answers:
Sati [7]3 years ago
6 0

Answer:

12000 Liters or 12 × 10^6 cubic centimeters

Explanation:

Multiply the volume value by 264.172

Please mark brainliest and have a great day!

BlackZzzverrR [31]3 years ago
5 0
13000 liters, 0.000012 cm3 or ml or cc
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A set of orbital for which the quantum number l=2 is
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Answer:

The second quantum number, known as the angular or orbital quantum number, describes the subshell and gives the magnitude of the orbital angular momentum through the relation. In chemistry and spectroscopy, ℓ = 0 is called an s orbital, ℓ = 1 a p orbital, ℓ = 2 a d orbital, and ℓ = 3 an f orbital.

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Describe the relationship between potential and kinetic energy
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NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc​
eduard

\tt Kp=Kc(RT)^{\Delta n}

NH₄Cl (s) ⇔ NH₃ (g) + HCl (g)

Δn = 2 (gas only)

R = 0.082

T = 427 + 273 = 700 K

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7 0
2 years ago
How would you describe the sequence of reactions in a hydrogen bomb
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3 years ago
The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.320 M NaOH. What is the init
yan [13]

This question is incomplete, the complete question is;

The flask contains 10.0mL of HCl and a few drops of phenolphthalein indicator.

The buret contains 0.320 M NaOH,

It requires 11.2 mL of the NaOH solution to reach the end point of the titration

What is the initial concentration of HCI?

Answer:  

initial concentration of HCl is 0.3584 M

Explanation:

Given that;

the reaction between HCl and NaOH is 1:1 molar

HCl(aq) + NaOH(aq) -------> NaCl(aq) + H2O(l)

we know that molarity is the number of moles of solute per liter of solution

so moles of NaOH consumed

= ( 0.320 mol / 1000ml) × 11.2ml

= 0.003584 mol

now

0.003584 moles of NaOH reacts with 0.003584 moles of HCl

moles of HCl present in the 10.0ml solution = 0.003584 mol

therefore the initial concentration of HCl

= ( 0.003584 mol / 10.0ml )× 1000ml

= 0.3584 M

the initial concentration of HCl is 0.3584 M

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