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Hunter-Best [27]
3 years ago
13

Which of the following was NOT used in support of the continental drift hypothesis?

Chemistry
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

fossil evidence

fit of South America and Africa

Explanation: can i have brainlist please

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Which of the following statements is true about both nuclear fusion and nuclear fission? They occur in the sun. Heavy atoms are
galina1969 [7]
<h2>Answer </h2>

Some mass changes into energy

<u>Explanation </u>

Some mass changes into energy are true about both nuclear fusion and nuclear fission. These both reactions produce large amounts of energy. Nuclear fusion is the process in which two light nuclei combine to form a larger nucleus. On the other hand, nuclear fission is reverse in which a heavy nucleus breaks into two light nuclei. Nuclear decay and transmission are also types of nuclear reactions. The matter is not destroyed in nuclear reactions.

6 0
4 years ago
Liquid bromine is added to sodium iodide crystals
gulaghasi [49]

The following chemical reaction will occur:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.

The chemical reaction is:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

(l) - liquid

(s) - solid

Learn more about:

balancing chemical equations

brainly.com/question/13971935

#learnwithBrainly

6 0
3 years ago
You have a cup of tea (250 ml) that is 375 K which is too hot to drink. It needs to be cooled to 350 K before you can drink it.
S_A_V [24]

Answer:

The hot tea should transfer <em>25.63 kJ</em> the surroundings to cool the tea.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).

m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.

c is the specific heat of the hot tea (c = 4.10 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).

<em>∴ Q = m.c.ΔT</em> = (250 g)(4.10 J/°C.g)(-25°C)) = <em>- 25630 J = - 25.63 kJ.</em>

<em>So, the hot tea should transfer 25.63 kJ the surroundings to cool the tea.</em>

4 0
3 years ago
If a 50.0 mL sample of gas exerts a pressure of 0.59 atm at 35.0 Celsius. What volume will the gas occupy at STP?
Rudik [331]

Explanation:

P1V1/T1 =P2V2/T2

V2 =P1V1T2/P2T1

0.59×0.05×273/1×308

V2 =0.03L

8 0
3 years ago
Can u see water vapour by a microscope?
tigry1 [53]

Answer:

It can be formed either through a process of evaporation or sublimation. Unlike clouds, fog, or mist which are simply suspended particles of liquid water in the air, water vapour itself cannot be seen because it is in gaseous form

Explanation:

hope it help

3 0
3 years ago
Read 2 more answers
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