Answer:
56,500,000.
Step-by-step explanation:
56,477,812 rounded to the nearest hundred thousand:
The 4 is in the hundred thousands place, so we'll look at the next digit to the right of that, which is the 7:
56,<u>4</u>77,812
Since 7 is more than 5, we'll have to go up a number, which will be the 4. Afterwards, we'll have to replace all the digits after the 4 with zeros.
56,500,000.
2 because 8 divided by 4 is 2.
The second one would be the answer. You want to plug in for this question. You can divide over the five leaving you with (x-2)^2 =25. Since you are squaring this answer, you want to get either 5 or negative five. Both -3 and 7 will do that.
Answer:
suuurrre vast resvon!!!!!!!!
Answer:
65°
Step-by-step explanation:
Radii CA and CB are perpendicular to tangent lines AT and BT, so
![\angle CAT=\angle CBT=90^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20CAT%3D%5Cangle%20CBT%3D90%5E%7B%5Ccirc%7D)
Since angle BAT is equal to 65°, angle CAB has measure
![\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.](https://tex.z-dn.net/?f=%5Cangle%20CAB%3D90%5E%7B%5Ccirc%7D-65%5E%7B%5Ccirc%7D%3D25%5E%7B%5Ccirc%7D.)
Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus
![\angle CBA=\angle CAB=25^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20CBA%3D%5Cangle%20CAB%3D25%5E%7B%5Ccirc%7D)
The sum of the measures of all interior angles in triangle is always 180°, so
![\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20CAB%2B%5Cangle%20CBA%2B%5Cangle%20ACB%3D180%5E%7B%5Ccirc%7D%5C%5C%20%5C%5C25%5E%7B%5Ccirc%7D%2B25%5E%7B%5Ccirc%7D%2B%5Cangle%20ACB%3D180%5E%7B%5Ccirc%7D%5C%5C%20%5C%5C%5Cangle%20ACB%3D130%5E%7B%5Ccirc%7D)
Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so
![x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}](https://tex.z-dn.net/?f=x%3D%5Cangle%20APB%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%20130%5E%7B%5Ccirc%7D%3D65%5E%7B%5Ccirc%7D)