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devlian [24]
3 years ago
13

Express 4.005 X 102 in standard notation.

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

4.0851 × 10²

Step-by-step explanation:

4.005 × 102

= 400.5 + 8.01

= 408.51

= 4.0851 × 10²

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300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
HELP!! PLZ!! I need to get get this right to pass the 6th grade plz help
Harman [31]
23% it shows you what it is right there :)
8 0
3 years ago
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What grade do you learn imaginary numbers?
nikdorinn [45]

Imaginary numbers are taught in high school algebra, which I think imaginary numbers are taught in 10th or 11th grade.

6 0
3 years ago
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8 star fruit cost $16. How many star fruit can you buy for $8?
kompoz [17]

Answer:

4 star fruit.

Step-by-step explanation:

16/8 = 2

each star fruit is 2 dollars

so 8/2 = 4

you can buy 4 star fruit for 8 dollars.

5 0
3 years ago
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A team played 38 matched in a football league. They won 22 matches and Lost nine matches. The rest of the matches were draws. Th
pychu [463]

Answer:

The answer is 73.

Step-by-step explanation:

To find the total number of points for a win, you would do 3*22 which equals 66.

Then the number of draws, which is 7 draws, has one point per draw, so it would be 7.

Add 66 by 7=73

Hope this helps!

4 0
3 years ago
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