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son4ous [18]
3 years ago
9

What is the value of y in the equation 2(3y + 7 + 5) = 196 − 16?

Mathematics
2 answers:
kap26 [50]3 years ago
6 0
Solve your equation step-by-step.

2(3y+7+5)=196−16

Simplify both sides of the equation.

2(3y+7+5)=196−16

(2)(3y)+(2)(7)+(2)(5)=196+−16(Distribute)

6y+14+10=196+−16

(6y)+(14+10)=(196+−16)(Combine Like Terms)

6y+24=180

Subtract 24 from both sides.

6y+24−24=180−24

6y=156

Divide both sides by 6.

6y/6 = 156/6

y=26

ki77a [65]3 years ago
4 0
First you want to figure out 196- 16.  That will give you 180.  Now divide 180 by 2, which is 90.  So the numbers in the parentheses have to add up to 90.  Now you want to add 7 and 5.  This will give you twelve.  Then subtract 12 from 90 to get 78.  78 divided by 3 will give you nine.  78 divided by 3 is 26, so y would be equal to 26.
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