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Tju [1.3M]
3 years ago
8

Find the domain of the equations. do not solve​

Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

x≥3, where x≠5

Step-by-step explanation:

x≥3, where x≠5

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8.5 written as a decimal??
Galina-37 [17]
Its already written as a decimal but it can be 8 1/2
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3 years ago
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Consider △RST and △RYX. If the triangles are similar, which must be true? A. RY/YS=RX/XT=XY/TS B.RY/RS=RX/RT=XY/TS C.RY/RS=RX/RT
trasher [3.6K]

Answer:

B.RY/RS=RX/RT=XY/TS

Step-by-step explanation:

If Triangles RST and RYX are similar, then the ratio of their corresponding sides is:

\dfrac{RS}{RY}= \dfrac{ST}{YX}=\dfrac{RT}{RX}\\$This could also be written by switching the numerator and denominators as:\\\dfrac{RY}{RS}= \dfrac{XY}{TS}=\dfrac{RX}{RT}

Out of the given options, Option B is true.

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3 years ago
Someone please explain (:
GaryK [48]

Answer:

a.) 1.38 seconds

b.) 17.59ft

Step-by-step explanation:

h(t) = -16t^2 + 22.08t + 6

if we were to graph this, the vertex of the function would be the point, which if we substituted into the function would give us the maximum height.

to find the vertex, since we are dealing with something called "quadratic form" ax^2+bx+c, we can use a formula to find the vertex

-b/2a

b=22.08

a=-16

-22.08/-16, we get 1.38 when the minuses cancel out. since our x is time, it will be 1.38 seconds

now since the vertex is 1.38, we can substitute 1.38 into the function to find the maximum height.

h(1.38)= -16(1.38)^2 + 22.08t + 6 -----> is maximum height.

approximately = 17.59ft -------> calculator used, and rounded to 2 significant figures.

for c the time can be equal to (69+sqrt(8511))/100, as the negative version would be incompatible since we are talking about time. or if you wanted a rounded decimal, approx 1.62 seconds.

7 0
3 years ago
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seropon [69]
34255   = 5 * 13 * 17 * 31
203515 = 5 * 13 * 31 * 101

So GCD(34255, 203515) = 5 * 13 * 31 = 2015
4 0
3 years ago
Consider the given function and the given interval. f\(x\) = 2 sin\(x\) - sin\(2 x\) text(, ) [0 text(, ) pi] (a) Find the avera
Finger [1]

a. The average value of f on the given interval is

\displaystyle f_{\rm ave}=\frac1{\pi-0}\int_0^\pi(2\sin x-\sin2x)\,\mathrm dx=\boxed{\frac4\pi}

b. Solve for c:

\dfrac4\pi=2\sin c-\sin2c\implies\boxed{c\approx1.238\text{ or }c\approx2.808}

4 0
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