9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
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7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
The range of the function is the set of all possible outputs, that is, the set of all values obtained by applying the function to elements of the domain. So the set of all values which can be obtained by applying h(x) to an element of its domain is {−4,0,5,60} , and thus that is the range of h(x) .
The correct answer to this question is: " A valid reason why the quadrilateral shown below is a parallelogram is that "B. All pairs of consecutive angles are supplementary."
The choices are:
A. Both pairs of opposite angles are congruent
B. All pairs of consecutive angles are supplementary
C. Both pairs of opposite sides are parallel
D. All pairs of consecutive angles are complementary
