3/-3 = -1 I got this by dividing 3 by 3, but since it is -3 that means your answer will be negative. your answer is -1.
hope this helped you!!
Answer:
Step-by-step explanation:
Given: quadrilateral ABCD inscribed in a circle
To Prove:
1. ∠A and ∠C are supplementary.
2. ∠B and ∠D are supplementary.
Construction : Join AC and BD.
Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,
∠1=∠2-----(1)
∠3=∠4-----(2)
∠5=∠6-------(3)
∠7=∠8------(4)
Also, sum of angles of quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4
→→→2∠1+2∠4+2∠6+2∠8=360°
→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,
→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)
As, ∠A+∠B+∠C+∠D=360°
∠A+∠C+180°=360°
∠A+∠C=360°-180°------Using A
∠A+∠C=180°
Hence proved.
credit: someone else
Answer:
Step-by-step explanation:
Remember that in the geometric serie if | r | < 1 the serie converges and if | r | ≥1 the serie diverges.
I suppose that the serie starts at 0, so using the geometric serie with r = | 
| > 1 the serie diverges.
Answer:
1
Step-by-step explanation:
move up one and over one, 1/1 = 1
Answer:
If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary . ... When two lines are cut by a transversal, the pairs of angles on either side of the transversal and outside the two lines are called the alternate exterior angles .
Step-by-step explanation:
hope this helps you :)
