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MakcuM [25]
3 years ago
5

What is the least common denominator of the four fractions listed below?

Mathematics
1 answer:
gogolik [260]3 years ago
7 0
100. 10 times 10 is 100. 25 times 4 is 100, and 4 times 25 is 100.
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You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim
Paraphin [41]
\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$2\\
P=\textit{original amount}\to& \$25\\
r=rate \\
t=years\to &\frac{1}{2}
\end{cases}

bearing in mind, "t" is in years, 6months is just 1/2 year

solve for "r", you'd get a decimal amount, multiply times 100, to get the percentage form
5 0
3 years ago
Read 2 more answers
Please help me asap!!!
fenix001 [56]

Answer:

Already answered it

Step-by-step explanation:

6 0
2 years ago
If ORBIT is coded BEOVG, then how is PLANET coded? /
arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

C = (P + o) \text{mod} 26

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so P = 15.

B is the 2nd letter in the alphabet, so C = 2

C = (P + o) \text{mod} 26

2 = (15 + o) \text{mod} 26

|o = |2-15| \text{mod} 26

o = 13

So

C = (P + 13) \text{mod} 26

PLANET:

P

P is the 16th letter in the alphabet.

C = (16 + 13) \text{mod} 26 = 3

So P is coded C.

L

L is the 12th letter in the alphabet:

C = (12 + 13) \text{mod} 26 = 25

L is coded Y(25th letter in the alphabet)

A

A is the 1st letter in the alphabet

C = (1 + 13) \text{mod} 26 = 14

A is coded N

N

N is the 14th letter in the alphabet

C = (14 + 13) \text{mod} 26 = 1

N is coded A

E

E is the 5th letter in the alphabet

C = (5 + 13) \text{mod} 26 = 18

E is coded R

So the correct answer is:

1. CYNARG

4 0
3 years ago
A candy jar contains flavored jelly beans. There are 7 orange, 9 cherry, 3 lemon, 15 licorice, and 6 blueberry. Find the probabi
Alisiya [41]

Answer: 0.046

Step-by-step explanation:

From the question,

orange jelly beans= 7

Cherry jelly beans =9

Lemon jelly beans = 3

Licorice jelly beans = 15

Blueberry jelly beans = 6

Total jelly beans = 40

The probability of choosing the first cherry jelly beans will be = 9/40

After the first one is chosen, there'll be 8 cherry jelly beans and total of 39 left. The probability of choosing the second one will be = 8/39

The probability of choosing two cherry jelly beans in a row will be:

= 9/40 × 8/39

= 72/1560

= 0.046

4 0
3 years ago
One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air
Lisa [10]

Answer:

P(A) = 0.45

P(B) = 0.32

Step-by-step explanation:

Given

P(A) > P(B)

P(A\ u\ B) = 0.626

P(A\ n\ B) = 0.144

Required

Find P(A) and P(B)

We have that:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

and

P(A\ n\ B) = P(A) * P(B) --- (2)

The equations become:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

0.626 = P(A) + P(B) - 0.144

Collect like terms

P(A) + P(B) = 0.626 + 0.144

P(A) + P(B) = 0.770

Make P(A) the subject

P(A) = 0.770 - P(B)

P(A\ n\ B) = P(A) * P(B) --- (2)

0.144 = P(A) * P(B)

P(A) * P(B) = 0.144

Substitute: P(A) = 0.770 - P(B)

[0.770 - P(B)] * P(B) = 0.144

Open bracket

0.770P(B) - P(B)^2 = 0.144

Represent P(B) with x

0.770x - x^2 = 0.144

Rewrite as:

x^2 - 0.770x + 0.144 = 0

Expand

x^2 - 0.45x - 0.32x + 0.144 = 0

Factorize:

x[x - 0.45] - 0.32[x - 0.45]= 0

Factor out x - 0.45

[x - 0.32][x - 0.45]= 0

Split

x - 0.32= 0 \ or\ x - 0.45= 0

Solve for x

x = 0.32\ or\ x = 0.45

Recall that:

P(B) = x

So, we have:

P(B) = 0.32 \ or \ P(B) = 0.45

Recall that:

P(A) = 0.770 - P(B)

So, we have:

P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45

P(A) = 0.45 \ or\ P(A) =0.32

Since:

P(A) > P(B)

Then:

P(A) = 0.45

P(B) = 0.32

6 0
2 years ago
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