When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
x = 1
Step-by-step explanation:
1 + x = 2
Subtract 1 form both sides,
1 + x - 1 = 2 - 1
x = 1
Answer: (-1/5, 2/5)
Step-by-step explanation:
See the photo for explanation and work.
Answer:
ok what is it
Step-by-step explanation:
