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PSYCHO15rus [73]
3 years ago
14

Find the value of 7 + 32 (-5 + 1) ÷ 2. A. 25 B. 32 C. -11

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

  • as written, -57
  • as perhaps intended, C. -11

Step-by-step explanation:

The expression shown evaluates as ...

  7 + 32(-5 +1)/2 = 7 +32(-4)/2 = 7 -128/2 = 7 -64 = -57

_____

If we assume your "32" is supposed to be 3², or 3^2, then the expression evaluates differently:

  7 +3²(-5 +1)/2 = 7 + 9(-4)/2 = 7 -36/2 = 7 -18 = -11 . . . . matches choice C

_____

When in doubt, you can have the Google calculator evaluate your expression. However, you do have to write it properly and with all the required parentheses.

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Use Fermat's Little Theorem to determine 7^542 mod 13.
m_a_m_a [10]

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How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

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