Find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30
1 answer:
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Answer:
10
Step-by-step explanation:
first you need to find the prime factors of the three numbers
ex:
prime factor of 18=
prime of 24=
there is one 2 and one 3 in common
greatest common multiple 2*3=6
so the greatest common multiple is ten because it is the only one that can divide between all three evenly.
so 10 is your answer
300 messages would have to be sent or received in order for the plan to cost same each month.
Step-by-step explanation:
Given,
Cost per month = $30
Per text sent or received charges = $0.10
Let,
x be the number of texts sent or received.
A(x) = 0.10x+30
A comparable plan costs = $60 per month
Text messages are unlimited.
B(x) = 60
For the two plans to cost equal;
A(x) = B(x)
Dividing both sides by 0.10
300 messages would have to be sent or received in order for the plan to cost same each month.
Keywords: function, addition
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