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Stella [2.4K]
3 years ago
15

A trader made a profit of 24% by selling an article for 3,720cedis how much should he have sold it to make a profit of 48%​

Mathematics
1 answer:
arsen [322]3 years ago
6 0
The answer is 7440
24%=3720
48%= 3720*2
48% = 7440
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The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
Given GH with endpoints (-7,3) andH (7. - 11), what are the coordinates of the<br> mielpoint of GH?
Y_Kistochka [10]

Answer:

Midpoint is (0, -4)

Step-by-step explanation:

x-coordinate of midpoint = (-7 + 7)/2 = 0/2 = 0

y-coordinate of midpoint = (3 - 11)/2 = -8/2 = -4

Midpoint is (0, -4)

8 0
3 years ago
Read 2 more answers
If there are 3 classrooms that each have 25 desks and there are a total of 87 students, how many more desks need to be added to
Reptile [31]

Answer:

12

Step-by-step explanation:

If there are 3 classrooms that each have 25 desks and there are a total of 87 students, how many more desks need to be added to a 4th classroom, that was originally empty, so that each of the students has a desk to sit in?

25 * 3 = 75

87 - 75 = 12

5 0
3 years ago
A pharmacist receives a shipment of 22 bottles of a drug and has 3 of the bottles tested. If 5 of the 22 bottles are contaminate
Norma-Jean [14]

Answer:

There is a 44.16% probability that exactly 1 of the tested bottles is contaminated.

Step-by-step explanation:

C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, we have that:

Total number of combinations:

C_{22,3} = \frac{22!}{3!(18)!} = 1540

Desired combinations:

It is 1 one 5(contamined) and 2 of 17(non contamined). So:

C_{5,1}*C_{17,2} = 5*17*8 = 680

What is the probability that exactly 1 of the tested bottles is contaminated?

P = \frac{680}{1540} = 0.4416

There is a 44.16% probability that exactly 1 of the tested bottles is contaminated.

5 0
3 years ago
What is the constant of proportionality in this proportional relationship
Nikitich [7]

Answer:

the answer is two

Step-by-step explanation:

3 0
2 years ago
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