HELP PLEASE???!!!!!!!

Mathematics

1 answer:

Fiesta28 [93]3 years ago

7 0

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=\dfrac{3}{4}x-12&(1)\\y=-4x-31&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\\dfrac{3}{4}x-12=-4x-31\qquad\text{multiply both sides by 4}\\\\3x-48=-16x-124\qquad\text{add 48 to both sides}\\\\3x=-16x-76\qquad\text{add}\ 16x\ \text{to both sides}\\\\19x=-76\qquad\text{divide both sides by 19}\\\\x=-4\\\\\text{Put it to (2):}\\\\y=-4(-4)-31\\y=16-31\\y=-15$

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My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??

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Step-by-step explanation:

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anastassius [24]

Question:

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Answer:

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