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Andrej [43]
3 years ago
14

a rectangular photograph is 4 inches wide and 6 inches long. The photograph is enlarged by increasing the length and width by an

equal amount. If the area of the new photograph is twice as large as the oringinal area, what are the dimensions of the new photograph?
Mathematics
1 answer:
olga2289 [7]3 years ago
7 0
The original area is
4*6= 24
The new area is 24*2 =48
So the dimensions is 6*8
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x = 15.7945

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

Angle θ = 33°

Opposite Leg = <em>x</em>

Hypotenuse = 29

<u>Step 2: Find Angle</u>

  1. Substitute in variables [sine]:                                                                           sin33° = x/29
  2. [Multiplication Property of Equality] Multiply 29 on both sides:                    29sin33° = x
  3. Rewrite:                                                                                                             x = 29sin33°
  4. Evaluate:                                                                                                           x = 15.7945
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