$a_0=600\\\\a_1=a_0 \cdot \boxed{\dfrac{1}{2}} = 300 = 600 \cdot \boxed{\dfrac{1}{2}}\\\\a_2=a_1 \cdot \boxed{\dfrac{1}{2}} = 150= 300 \cdot \boxed{\dfrac{1}{2}}\\\\a_3=a_2 \cdot \boxed{\dfrac{1}{2}} = 75 = 150 \cdot \boxed{\dfrac{1}{2}}$

So, the explicit formula is for n

$\boxed{a_n=a_0\cdot \left(\dfrac{1}{2}\right)^n=600\cdot \left(\dfrac{1}{2}\right)^n}}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

The answer to the problem i asked

guapka [62]

8(4x+5)=136
Multiply the number outside of the parenthesis(8) with the numbers inside the parenthesis(4x and 5).
32x+40=136
Subtract 40 from both sides
32x=96
Divide both sides by 32 so the only thing remaining on the side of the variable is only the variable itself.
Final Answer: x= 3

8 0

3 years ago