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3 years ago

5/7x-4=21 solve folve for x

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

7*x-4-(21)=0

Solve : 7x-25 = 0

Add 25 to both sides of the equation :

7x = 25

Divide both sides of the equation by 7:

x = 25/7 = 3.571

Marysya12 [62]3 years ago

5 0

Answer:

Step-by-step explanation:

1. 5/7x - 4 = 21

2. Add 4 on both sides --> 5/7x = 25

3. Divide by 5/7 on each side

4. on the left it cancels out and you are left with ---> x = 35

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Which exponential equation is equivalent to the logarithmic equation below?

julsineya [31]

Answer:

$\implies\boxed{ 10^a = 300 }$

Step-by-step explanation:

We are provided logarithmic equation , which is ,

$\implies log_{10}^{300}= a$

Here we took the base as 10 , since nothing is mentioned about that in Question .

Say if we have a expoteintial equation ,

$\implies a^m = n$

In logarithmic form it is ,

$\implies log_a^n = m$

Similarly our required answer will be ,

$\implies\boxed{ 10^a = 300 }$

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2 years ago

Tomnhas read 11 pages of a 215 page book he will read 6 pages each day until he fi ishes the book which equation can be used to

Ierofanga [76]

Answer: 34 days

Step-by-step explanation:

To find out the amount of pages he needs to read each day at the rate of 6 pages/day is 204/6. (we divide 204 by 6 because that is 215-11, since he already read 11 pages) this is 34

5 0

2 years ago

What is the solution of the equation -14+2x+3=4x-13-7x

Harman [31]

Answer: x= -2/5 or x= -0.4

combine like terms on left side and get -11+2x. then combine terms on right side and get -13-3x. add the 11 to the right side and get 2x= -2-3x

then add over the 3x and get 5x=-2

and finally divide the -2 from 5x and get -2/5

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3 years ago

A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average

larisa [96]

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: $\mu \leq 94$

Alternate Hypothesis: $\mu > 94$

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

$t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

Using the values, we get:

$t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245$

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

$\alpha =0.05$

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

3 0

3 years ago

a group of students surveyed chose baseball and soccer as their favorite sport in the ratio 3:8. if 132 students were surveyed f

DerKrebs [107]

132 people surveyed
132 ÷ (8+3)
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12 x 8
96 people choose soccer

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3 years ago