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3 years ago

7

"The last time I bought this product, it cost $20.00 but it looks like it costs $29.60 today. Why such a large increase?"

1 answer:

Oksanka [162]3 years ago

5 0

Answer:

The company decided to increase the price by $9.60, or by 48%.

Step-by-step explanation:

To measure the price difference in dollars is simple, just subtract the old price from the new one:

$29.60 - 20 = 9.60$

Divide the price change by the old price to find the price increase in percentage:

$9.60 \div 20 = 0.48 \\ 0.48 \times 100\% = 48\%$

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3 years ago

Brian made 5 free throws at basketball practice. ethan scored 3 more than twice the number of free throws brian made. which equa

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3 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

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3 years ago

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harkovskaia [24]

Answer:

D

Step-by-step explanation:

The rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

Shows that when 2 powers with the same base are being multiplied then the exponents are added.

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