C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?

1 answer:

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The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
C2D3
= (2x)2(3x)3
= 108x5 

Then set that equation equal to your solubility constant 

9.14x10-9 = 108x5 
x = 9.67x10-3

So the molar solubility is 9.67x10-3

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The circle below is center Ed at O. Decide which length,if any, is definitely the same as the length. a) AD. b) BC. Justify your

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Answer:

Point O is the center of the circle.

Part (a)

$\overline{A\:\!F}$ is a chord.

$\overline{OD}$ is a segment of the radius and is perpendicular to $\overline{A\:\!F}$

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, $\overline{AD}=\overline{DF}$

Part (b)

If $\overline{BE}$ was extended past point E to touch the circumference it would be a chord.

As $\overline{OC}$ is perpendicular to $\overline{BE}$ , it would bisect the chord, but as $\overline{BE}$ is only a portion of a chord, $\overline{OC}$ does not bisect $\overline{BE}$ .