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sweet [91]
3 years ago
14

C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
4 0
The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>

<span>Then set that equation equal to your solubility constant </span>

<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3 
</span>
<span>So the molar solubility is 9.67x10-3</span>
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Angle J and angle M are base angles of an isosceles trapezoid JKLM. If angle J=20x+9 and angle M =14x+15, find angle K
anzhelika [568]
K or l will be 151 degrees.

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5 0
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6t - 5 + 5t = 105 (t = 4; t = 7;t = 10)
mart [117]

Answer:

t = 10

Step-by-step explanation:

6[10] - 5 + 5[10] = 105 \\  \\ 60 - 5 + 50 = 105 \\  \\ 105 = 105

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3 years ago
Simplify the expression:<br><br> 3x (4x-6)<br> —————<br> 2x(3x)
Marina86 [1]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
9th question help ?!
Daniel [21]
Hey there! :)

You have to find the area of all of them and add it together.

Formulas:

Area of a square: l · w
Area of a triangle: (b · h) ÷ 2

Square - 

l = 3
w = 3

3 × 3 = 9

Triangle - 

b = 3
h = 3

(3 × 3) ÷ 2
    9  ÷    2   = 4.5

There are 4 triangles

4.5 × 4 = 18

9 + 18 = 27

The surface area ⇒ 27 cm²



5 0
3 years ago
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