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iris [78.8K]
3 years ago
6

le" class="latex-formula">
Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

x=11/2

Step-by-step explanation:

First we can combine similar terms on the left side. 3x + x is 4x and 20-15 is 5

Now that we have combined them, we are left with 4x+5=27

Subtract 5 on both sides to cancel out the 5.

4x=22

Divide both sides by 4

x=22/4

Simplify

x=11/2

sasho [114]3 years ago
6 0

Answer:

\boxed{\sf x = \frac{11}{2}}

Step-by-step explanation:

\sf Solve \:  for  \: x: \\  \sf \implies 20 + 3x - 15 + x = 27 \\  \\  \sf Grouping \:  like  \: terms, \: 20 + 3x - 15 + x = \\  \sf (3x + x) + (20 - 15) : \\  \sf \implies  \boxed{ \sf (3x + x) + (20 - 15)} = 27 \\  \\  \sf 3x + x = 4x :  \\  \sf \implies \boxed{ \sf 4x} + (20 - 15) = 27 \\  \\  \sf 20 - 15 = 5 :  \\  \sf \implies  4x +  \boxed{ \sf 5} = 27 \\  \\  \sf Subtract \:  5 \:  from  \: both \:  sides: \\  \sf \implies 4x + (5 -  \boxed{ \sf 5}) = 27 -  \boxed{ \sf 5} \\  \\  \sf 5 - 5 = 0 :  \\  \sf \implies 4x = 27 - 5 \\  \\  \sf 27 - 5 = 22 :  \\  \sf \implies 4x =  \boxed{ \sf 22} \\  \\  \sf Divide  \: both \:  sides \:  of \: 4x = 22 \: by \: 4 :  \\  \sf \implies  \frac{4x}{4}  =  \frac{22}{4}  \\  \\  \sf \frac{ \cancel{4}}{ \cancel{4}}  = 1 :  \\  \sf \implies x =  \frac{22}{4}  \\  \\ \sf \implies x =  \frac{11 \times  \cancel{2}}{2 \times  \cancel{2}} \sf \implies x = \frac{11}{2}

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Solve for x<br><img src="https://tex.z-dn.net/?f=6x%20-%202%20%3D%204x%20%2B%2013" id="TexFormula1" title="6x - 2 = 4x + 13" alt
solniwko [45]

x = \frac{15}{2}

subtract 4x from both sides of the equation

6x - 4x - 2 = 13

2x - 2 = 13

add 2 to both sides

2x = 13 + 2 = 15

divide both sides by 2

x = \frac{15}{2}


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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
A strip is 5ft long and 2 feet wide. How much stripping is needed
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Because LxW=A

so we did 5x2=10

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