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Viktor [21]
3 years ago
10

Which of these are accepted as a true without proof?

Mathematics
2 answers:
devlian [24]3 years ago
7 0
Postulate is a statement accepted true without a proof.

Hope this helps :)<span />
azamat3 years ago
6 0
Postulate is statement that is accepted to be true without proof.
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PLEASE HELP<br><br> Which of the following questions are correct? Select all that apply.
gregori [183]

Answer:

I think A and D are both correct

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3 years ago
Solve for x<br><br> 2x+3+5x=24 <br> what is x?
Westkost [7]

Answer:

x=3

Step-by-step explanation:

2x+3+5x=24\\7x+3=24\\7x=21\\x=3

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Is -2 a solution of 2x+8=2?
Katarina [22]

Answer:2x+8=2

2x=2-8

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Step-by-step explanation:

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3 years ago
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Plz can you just answer c
Rasek [7]

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2 years ago
In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is
Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0
3 years ago
Read 2 more answers
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