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Dimas [21]
2 years ago
5

Landscaping company A charges a $50 fee plus $18 an hour and landscaping company B charges $20 per hour and a fee of $30. At how

many hours will the cost be the same for both companies
Mathematics
1 answer:
Inessa05 [86]2 years ago
3 0

\text{Hello there!}\\\\\text{In this question, we're trying to find when both companies cost the same}\\\\\text{We know that landscaping company A charges \$50 fee plus \$18 an hour}\\\\\text{That would be represented as:}\,\,y=18x+50\\\\\text{We know that landscaping company B charges \$20 per hour and a \$30 fee}\\\\\text{That would be represented as:}\,\,y=20x+30\\\\\text{We would get both equations, put them together, and solve}\\\\18x+50=20x+30\\\\\text{Solve:}\\\\18x+50=20x+30\\

\text{Subtract both sides by -20x}\\\\-2x+50=+30\\\\\text{Subtract both sides by 50}\\\\-2x=-20\\\\\text{Divide by -2}\\\\\large\boxed{x=10}\\\\\text{They're the same price at 10 hours}\\\\\text{I hope this helps!}\\\text{Best regards,}\\\text{MasterInvestor}

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nlexa [21]

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a. -1.7

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Step-by-step explanation:

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2 years ago
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NeX [460]
1) Which ratio is equivalent to [tex] \frac{4}{16} [tex]?
[tex] \frac{4}{16} * 2 = \frac{8}{32} [tex], or 8:32.

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286 = \frac{11x}{2}\\
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6 0
3 years ago
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stepladder [879]
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3 years ago
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inessss [21]

Answer:

Your answer is going to be x=4.

Step-by-step explanation:

5x+1=21

    -1  -1

(5x)/5=(20)/5

x=4

4 0
3 years ago
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svlad2 [7]
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2 years ago
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