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NISA [10]
3 years ago
13

Harry and Gwen ride in a bicycle race. Harry clocks 102.62 meters per minute, and Gwen clocks 101.94 meters per minute. What is

the difference in their cycling speeds?
Mathematics
1 answer:
viva [34]3 years ago
8 0
The difference in their cycling speeds is 0.68 meters per minute.
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The radius of a circle is 11 in. Find its area in terms of 7.​
Talja [164]

it is definitely 77 becuase 7 times 11 is 77

3 0
2 years ago
How to solve this equation <br> 8(4-x)= 7x+2
Andrews [41]
8 ( 4 - x ) = 7x + 2
32 - 8x = 7x + 2
      -7x     -7x
--------------------------
32 - 15x = 2
-32           -32
----------------------------
-15x = -30
/-15      /-15

x = 2.
3 0
3 years ago
Read 2 more answers
A 13-inch piece of ribbon is 33.02 centimeters long. How long will a 24-inch piece be?
m_a_m_a [10]

Answer:

60.96

Step-by-step explanation:

1 inch = 2.54

so to know what 24 inch = you can multiply 24 time 2.54 and you should get the answer

       

2.54 time 24= 60.96

5 0
2 years ago
Solve<br> x2 - 8x + 14 = 2x - 7
BabaBlast [244]

Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red
Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

  1. Urn 1 = 2 red + 4 white = 6 chips
  2. Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : \frac{1}{3} (2 red from 6 chips(2/6=1/2))

For a white one is: \frac{2}{3}(4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

  • First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
  • Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

  • In the first case the probability of taking a white one is of:  \frac{2}{5} = 40%  ( 2 whites of 5 chips)
  • In the second case the probability of taking a white one is of:  \frac{1}{5} = 20%  ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

\frac{4}{6} x \frac{2}{5} = \frac{4}{15} = 26.66%   ( \frac{4}{6} the probability of taking a white chip from the urn 1, \frac{2}{5}  the probability of taking a white chip from urn two)

For the second case we multiply:

\frac{1}{3} x \frac{1}{5} = \frac{1}{30} = .06%   ( \frac{1}{3} the probability of taking a red chip from the urn 1, \frac{1}{5}   the probability of taking a white chip from the urn two)

8 0
3 years ago
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