Yes because you use the distributive property
Answer: 22
Step-by-step explanation:
The <em>correct answers</em> are:
"Four and 11 hundredths" or "four and one hundred ten thousandths"; and
"Four and ten hundredths" or "four and one tenth."
Explanation:
In the first decimal, the digit 4 is in front of the decimal. This is read "Four and". After the decimal, we have 110. We look at the last place, digit, 0. Going by our place value, this is in the thousandths place. We read the block of digits 110 as "one hundred ten" and it is "thousandths." This makes the number "four and one hundred ten thousandths."
Alternatively, if we drop the zero, we would have 4.11. It is still "four and"; this time the last digit is 1, and it is in the hundredths place. 11 is read as "eleven", so this would be "four and eleven hundredths."
For the second number, 4.10, we have a 4 in front of the decimal, so we again have "four and". Our last digit is 0, and it is in the hundredths place; 10 is read "ten", so we have "four and ten hundredths."
Alternatively, if we drop the zero, we have 4.1. This is still "four and"; the 1 is now our last digit, and it is in the tenths place, so we have "four and one tenth."
0.83 * 100 = 83, so 0.83 = 83/100.
But in case you meant the slightly more interesting repeating decimal, 0.8333...:
Let <em>x</em> denote this number. Then
10<em>x</em> = 8.333...
100<em>x</em> = 83.333...
==> 100<em>x</em> - 10<em>x</em> = 83.333... - 8.333...
==> 90<em>x</em> = 83 - 8 = 75
==> <em>x</em> = 75/90 = 5/6
Answer:
(3x+2)(2x-5)(x³ -9)
Step-by-step explanation:
I like to use a graphing calculator to assist with factoring higher-degree polynomials. This polynomial has roots at -2/3, +5/2, and an irrational number near 2.08. The factors corresponding to the rational roots are (3x +2) and (2x -5).
Polynomial long division or synthetic division can be used to divide these out.
In each case, the divisor has a coefficient other than 1, so both dividend and divisor polynomials need to be divided by that coefficient before proceeding with synthetic division. (That is why there are fractions in the tableaux.)
The result is that the factorization in integers is ...

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The irrational roots are the three cube roots of 9, two of which are complex.
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Any of several different algorithms can tell you that the real roots will lie in the interval [-6, 6] or smaller. The rational roots will be of the form ...
±(divisor of 90)/(divisor of 6)