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Andreas93 [3]
2 years ago
13

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re

d, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]
Compute the probability that a randomly selected peanut M&M is not blue.

Correct


Compute the probability that a randomly selected peanut M&M is brown or yellow.

Correct


Compute the probability that two randomly selected peanut M&M’s are both orange.

Correct


If you randomly select two peanut M&M’s, compute that probability that neither of them are blue.

Incorrect

If you randomly select two peanut M&M’s, compute that probability that at least one of them is blue.
Mathematics
1 answer:
victus00 [196]2 years ago
8 0

Answer:

salution

Step-by-step explanation:

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Read 2 more answers
Can someone please help me? I don't understand how to solve this.
Scilla [17]

Answer:

  (5, 15)

Step-by-step explanation:

The problem statement tells you how to solve it. You are expected to know what the midpoint formula is.

You are given that (x, y) is the unknown end point. If (Mx, My) is the midpoint, and (x1, y1) is one end point, the midpoint formula tells you ...

  Mx = (x1 +x)/2

  My = (y1 +y)/2

__

Solving these equations for x and y, you get ...

  2Mx = x1 +x

  x = 2Mx -x1

Similarly, ...

  2My = y1 +y

  y = 2My -y1

__

Filling in the given coordinates, this becomes ...

  x = 2(-2) -(-9) = -4 +9 = 5

  y = 2(7) -(-1) = 14 +1 = 15

The other endpoint is (5, 15).

_____

<em>Additional comment</em>

I like to write the midpoint formula for points A and B as ...

  M = (A +B)/2

where A and B each represent an ordered pair (or triple, in 3 dimensions). The arithmetic is done element-by-element on the ordered pairs, so this formula is equivalent to the one above.

If you solve it for B, you get ...

  B = 2M - A . . . . the other endpoint given the midpoint and one endpoint

This might be a formula you want to add to your list of useful formulas in Algebra.

3 0
2 years ago
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