Theodore firs uses 1/2 of milk to make hot chocolate: 1 - 1/2 = 1/2. So 1/2 of milk is left. After that, he uses 3/2 of the milk he has left to make cookies. It means:
1/2 - ( 2/3 * 1/2 ) = 1/2 - 1/3 = 3/6 - 2/6 = 1/6
At the end 1/6 of the milk Theodore have left.
1/6 * 6 = 1 gallon
Answer: After making hot chocolate and the cookies 1 gallon of milk Theodore have left.
Answer:
First person: $107
Second person: $98
Third person: $93
Step-by-step explanation:
Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.
With the information given in the exercise, you can set up the following equations:
Equation 1 → 
Equation 2 → 
Equation 3 → 
Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":
Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".
Therefore, you get:
Answer:
45
Step-by-step explanation:
The different pairs of individual can be computed using rule of combination.
The combination is denotes as nCr.
nCr=n!/(r!(n-r)!)
In the given problem n=total candidates=10 and r= Selected candidates=2.
10C2=10!/(2!(10-2)!)
10C2=10*9*8!/(2!8!)
10C2=90/2
10C2=45
So, 45 different pairs of individuals can be selected.
Answer:
Step-by-step explanation: Since the given problem states that the two angles, angle 1 and angle 2 form a linear pair, this means that they form a 180° line, so that:
measure angle 1 + measure angle 2 = 180°
Since measure of angle 2 is six more than twice the measure of angle 1, therefore:
measure angle 2 = 2 (measure angle 1) + 6
hence, substituting this into the first equation:
measure angle 1 + 2 (measure angle 1) + 6 = 180
3 (measure angle 1) = 174
measure angle 1 = 58°
Therefore,
measure angle 2 = 2 (measure angle 1) + 6
measure angle 2 = 2 (58°) + 6
measure angle 2 = 122*
Answer:
Therefore option 2 is correct.
given:
- 4 huge blue blocks
- 5 medium red blocks
- 1 small yellow block, it will be 1
<u>solve</u>:
option 1:
(x + 4)(x + 1)
x² + 4x + x + 4
x² + 5x + 4
option 2:
(4x+1) (x+1)
4x² + 4x + x + 1
4x² + 5x + 1
option 3:
4x + 5
option 4:
( 4x² + x ) (x + 1)
4x³ + 4x² + x² + x
4x³ + 5x² + x
