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jasenka [17]
2 years ago
15

" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
lawyer [7]2 years ago
4 0

Answer:

115

Step-by-step explanation:

using Pemdas rule

here in this problem first multiply and then add

11 \times 9 = 99 \\ 99 + 16 = 115

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Pleaseeee help w these math questions! please show work!!!<br><br> 50 points
Schach [20]

9. You need an exact answer. So I will give you it but I'll also give you an approximation because it might help you understand it more.

Because we know the cosine fo theta, we can evaluate the inverse cosine of -2/3 first to find theta.

sin^{-1}(-2/3) = 131.81° approx.

Because 131.81° is in the second quadrant its third quadrant partner is 228.19°. Which would make the sine 0.75 approximately.

But we need an exact answer I suppose so which is this disgusting mess...sin(2\pi -cos^{-1}(\frac{-2}{3})). I know it looks scary but it is basically  all the steps we just did but without evaluating anything.

This can be simplified using: sin(x− y) = sinxcosy−cosxsiny

To... -sin(cos^{-1}(\frac{-2}{3}))

answer: -sin(cos^{-1}(\frac{-2}{3}))

10. Okay. So because we have a point we can say that...

θ = tan^{-1}(-9/11)

sin(θ) = +sin(tan^{-1}(-9/11))

11. arcsin(-0.37) = sin^{-1}(-0.37) = -21.72°+2kπ or 201.72°+2kπ approx. where k has to be an integer

answer: idk if you want one or more solutions so I gave you them all.

12. arccos(-√3/2) = cos^{-1}(\frac{-\sqrt{3} }{2}) = \frac{5\pi }{6}+2k\pi, \frac{7\pi }{6}+2k\pi

Remember that "k" must be an integer.

answer: 5π/6

6 0
3 years ago
Need help right now asap??!?!?!??!?!??!
abruzzese [7]

A) The person that has a greater probability of selecting a quadrilateral is Robert.

B) The person that has a greater probability of selecting a polygon is; Robert.

C) The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

<h3>How to Identify Polygons?</h3>

Sandy has; Square, Rhombus, Equilateral Triangle, Regular Hexagon

Robert has Scalene Triangle, Kite, Right Isosceles Triangle, Isosceles Trapezoid, Quadrilateral.

A) Sandy's probability of selecting a quadrilateral = 2/4 = 0.5

Robert's probability of selecting a quadrilateral = 3/5 = 0.6

The person that has a greater probability of selecting a quadrilateral is Robert

B) The person that has a greater probability of selecting a polygon is; Robert because he has more.

C) Probability of Sandy selecting a polygon with at least 2 sides parallel is; 3/4 = 0.75

The Probability of Robert selecting a polygon with at least 2 sides parallel is; 2/5 = 0.4

The event that is more likely to happen is the Probability of Sandy selecting a polygon with at least 2 sides parallel.

Read more about Polygons at; brainly.com/question/5715879

#SPJ1

6 0
2 years ago
Determine the vertex- f( x)= x^2 +4x +3<br><br> (2,-1)<br> (-2, -1)<br> (-3, -1)<br> (-1, -2)
Grace [21]

The answer is ( -2 , -1 ) .

Hope it's helped ♥️♥️♥️♥️♥️.

8 0
3 years ago
4(x+9)=8x-7<br> Solve for x
valentina_108 [34]

Answer:

x = 10.75

Step-by-step explanation:

4(x+9)=8x-7

Step 1: Distribute the 4 to the x and 9

4 * x = 4x

4 * 9 = 36

We now have 4x + 36 = 8x - 7

Step 2: add 7 to both sides

36 + 7 = 43

-7 + 7 cancels out

We now have 4x + 43 = 8x

Step 3 subtract 4x from both sides

4x - 4x cancels out

8x - 4x = 4x

We now have 4x = 43

step 4 divide both sides by 4

4x / 4 ( the 4s cancel out and we're left with x )

43/4 = 10.75

We're left with x = 10.75

3 0
2 years ago
a town has 2 fire engines operating independently . the probability that a specific engine is available when needed is 0.96. wha
tester [92]

Answer:

The probability that neither is available when needed

P(A n B)^{c} = 0.04  

Step-by-step explanation:

A town has 2 fire engines operating independently

Given data  the probability that a specific engine is available when needed is 0.96.

Let A and B are the two events of two fire engines

given  P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)

Independent events : P( A n B) = P(A) P(B)

The probability that neither is available when needed

P(A n B)^{c} = 1- P(A n B)

P(A n B)^{c} = 1- 0.96 = 0.04

                                     

7 0
3 years ago
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