<span>f(x)=<span>x2</span>−1</span>That means to find the value of the function at any value of x, we square x and subtract 1. If <span>x=2a</span>, we square <span>2a</span> and subtract 1:<span>f(2a)=(2a<span>)2</span>−1=4<span>a2</span>−1</span>Now, we know that <span>f(2a)=35</span>so we can find the value of a:<span>f(2a)=(2a<span>)2</span>−1=4<span>a2</span>−1=35</span><span>4<span>a2</span>−1+1=35+1</span><span>4<span>a2</span>=36</span><span><span>a2</span>=9</span><span><span>a=±3</span></span>
Answer: x = (1,9]
Step-by-step explanation: If x is all real numbers greater than 1 (simply: x is greater but not equal to 1) then it is 1 < x. And if x is less than or equal to 9 then its x ≤ 9. To translate 1 < x ≤ 9 into interval notation, you need to keep in mind that parentheses are for these symbols: <>. And brackets are for these symbols: ≤≥. With that in mind, your answer is (1,9]. Also, keep in mind that interval notation goes from lowest value number to highest, so you wouldn’t write this notation as [9,1).
To evaluate 
, you'd start by rewriting this as 
and your first step of evaluation is to evaluate 
.
When you evaluate , you have the following:
and this is undefined. Since you cannot perform the first step of the evaluation, you cannot evaluate 
.
Yes...
x/3 > -1
what values of x make x/3 > -1
hint... your answer will look like like x > (number)
