Find the zeros of the function y=x^2-36

4p^2 without exponent

Usimov [2.4K]

Answer:

4p(p)

Step-by-step explanation:

7 0

4 years ago

Please help! I feel like I'm drowning :(

algol13

Answer:

1d = -3

2b = 2

2c = 1

3a = 3

3d = 4

Step-by-step explanation:

Polynomial 1: $x^2-8x+15$

Multiply the leading coefficient, 1, and the last term, 15. You get: 15.

Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:

Factors of 15: -5 * -3

Addends of -8: -5 + -3

Replace the -8x with -5x - 3x:

$x^2-5x-3x+15$

Put parentheses around the first 2 terms & last 2 terms and factor like so:

$(x^2-5x)-(3x+15)$

$x(x-5)-3(x-5)$

$(x-5)(x-3)$

Looking at the answer (ax + b)(cx + d), d would correspond with -3.

Polynomial 2: $2x^3-8x^2-24x$

First factor out the x:

$x(2x^{2}-8x-24)$

Divide the polynomial inside by 2 and place the 2 outside with the x:

$2x(x^2-4x-12)$

Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:

Factors of -12: -6 * 2

Addends of -4: -6 + 2

Replace the -8x with -6x + 2x:

$2x(x^2-6x+2x-12)$

Put parentheses around the first 2 terms & last 2 terms and factor like so:

$2x((x^2-6x)+(2x-12))$

$2x(x(x-6)+2(x-6))$

$2x((x+2)(x-6))$

$2x(x+2)(x-6)$

Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.

Polynomial 3: $6x^2+14x+4$

Divide the polynomial by 2:

$(2)(3x^2+7x+2)$

Find the factors of 3*2 and the addends of 7 and see which two numbers match:

Factors of 6: 6 * 1

Addends of 7: 6 + 1

Replace the 7x with 6x + x:

$(2)(3x^2+6x+x+2)$

Put parentheses around the first 2 terms & last 2 terms and factor like so:

$(2)((3x^2+6x)+(x+2))$

$(2)(3x(x+2)+(x+2))$

$(2)((3x+1)(x+2))$

$(2)(3x+1)(x+2)$

Then multiply the 2 with the (x+2) and here's your final answer:

$(3x+1)(2x+4))$

Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.

Hope that helps (●'◡'●)

(This took a while to write, sorry about that)

8 0

3 years ago

6th grade math, help me please.

natita [175]

Answer:

a) $\frac{2}{3} \,\frac{lb}{bread}$

b) $1\frac{1}{4} \,\frac{in}{domino}$

Step-by-step explanation:

Part a:

every 4 lbs of flour, she makes 6 loaves of bread. this as a rate in simplest fraction form is:

$\frac{4}{6} \,\frac{lb}{bread} = \frac{2}{3} \,\frac{lb}{bread}$

Part b:

every 10 inches , 8 dominoes can be placed. then the rate can be written as:

$\frac{10}{8} \,\frac{in}{domino} = \frac{5}{4} \,\frac{in}{domino} =1\frac{1}{4} \,\frac{in}{domino}$

7 0

3 years ago

Travis has decided to budget his spending money. He can spend no more than $ 143.15 every month. He has also decided to spend 5.

dalvyx [7]

Answer:m<$23.09

Step-by-step explanation: This question is tricky as there are unexplained variables.

Travis plans spending $143.15 every month but only two expenses were given to us, so other possible expenses may or may not be expended in this particular month.

That’s why we must include an inequality here.

Okay, back to the question.

Travis plans spending 5.2 times movie money on video games, my kinda dude.lol

Hence, 5.2m=v

m=movie budget

v=video games budget

But m+v<=143.15, the total proposed budget. Let’s replace v with 5.2m,

We have,

m+5.2m<=143.15

6.2m<=143.15

m<=23.0887

(We’ll have to approximate to the nearest cent)

m<$23.09

4 0

3 years ago

Suppose that in a casino game the payout is a random variable X . If X is positive, you gain money, if negative, you lose.

Vanyuwa [196]

Answer:

the conditional probability that X = 1 , X = 2 and X = 3 is 0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively

Step-by-step explanation:

a player wins money when i>0 then defining event W= gain money , then

P(W) = p(i>0) = p(1)+p(2)+p(3)

then the conditional probability can be calculated through the theorem of Bayes

P(X=1/W)= P(X=1 ∩ W)/P(W)

where

P(X=1 ∩ W)= probability that the payout is 1 and earns money

P(X=1 / W)= probability that the payout is 1 given money was earned

then

P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160 ) = 0.7333 (73.33%)

similarly

P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160 ) = 0.25 (25%)

P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160 ) = 0.0167 (1.67%)

8 0

4 years ago

Find the zeros of the function y=x^2-36​

Find the zeros of the function y=x^2-36