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forsale [732]
3 years ago
10

Which is greater than, -9/4 or -3?

Mathematics
2 answers:
Firdavs [7]3 years ago
7 0

-9/4 is greater than -3 because -9/4 is also -2.25 and the less negative number is always greater than the more negative number.

Hope this helps!


jeka57 [31]3 years ago
4 0
-9/4 is greater than -3
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Math help please please ​
Vika [28.1K]

Answer:

3(3x+1) (2x-1)

Step-by-step explanation:

18x^2 -3x-3

Factor out a 3

3(6x^2 -x-1)

3(3x+1) (2x-1)

6 0
4 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
Which set of angles can be used to construct a triangle?
Eddi Din [679]
Depends on what kind of a triangle
6 0
3 years ago
Read 2 more answers
Can someone please help me?
Luda [366]

Answer:

(x-1)^5 (x+1)

Step-by-step explanation:

2 (x-1)^5 + (x-1)^6

Factor out (x-1)^5

2 (x-1)^5 + (x-1)^5 (x-1)

(x-1)^5( 2 + x-1)

Combine like terms

(x-1)^5 (x+1)

4 0
3 years ago
Read 2 more answers
5+2 root 3 / 7+4 root 3 =a-6root3
STALIN [3.7K]

Answer:

<h2>a = 11</h2>

Step-by-step explanation:

\dfrac{5+2\sqrt3}{7+4\sqrt3}\qquad\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=\dfrac{5+2\sqrt3}{7+4\sqrt3}\cdot\dfrac{7-4\sqrt3}{7-4\sqrt3}=\dfrac{(5+2\sqrt3)(7-4\sqrt3)}{7^2-(4\sqrt3)^2}\qquad\text{use FOIL}\\\\=\dfrac{(5)(7)+(5)(-4\sqrt3)+(2\sqrt3)(7)+(2\sqrt3)(-4\sqrt3)}{49-4^2(\sqrt3)^2}\\\\=\dfrac{35-20\sqrt3+14\sqrt3-8(3)}{49-(16)(3)}=\dfrac{(35-24)+(-20\sqrt3+14\sqrt3)}{49-48}\\\\=\dfrac{11-6\sqrt3}{1}=11-6\sqrt3

8 0
3 years ago
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