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3 years ago

First down = 25 yards.

Mathematics

1 answer:

valentinak56 [21]3 years ago

3 0

This is the question.

At the start of the first down, the football was 25 yards from the Captains' end zone. During three downs, the ball moved 6 yards closer to their end zone, then 10 yards farther from it, and then 8 yards closer to it. How many yards from their end. zone was the ball at the end of the third down?

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Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre

artcher [175]

Answer: The proportion of new car buyers that trade in their old car has statistically significantly decreased.

Step-by-step explanation:

Since we have given that

p = 48% = 0.48

n = 115

x = 46

So, $\hat{p}=\dfrac{46}{115}=0.40$

So, hypothesis would be

$H_0:\ p=\hat{p}\\\\H_a:p$

So, test value would be

$z=\dfrac{p-\hat{p}}{\sqrt{\dfrac{p(1-p)}{n}}}\\\z=\dfrac{0.48-0.40}{\sqrt{\dfrac{0.48\times 0.52}{115}}}\\\\z=\dfrac{0.08}{0.0466}\\\\z=1.72$

At 10% level of significance, critical value would be

z= 1.28

Since 1.28 < 1.72

So, we will reject the null hypothesis.

Hence, the proportion of new car buyers that trade in their old car has statistically significantly decreased.

6 0

4 years ago

The coordinates of the vertices of triangle ABC are A(-1,3), B(1,2) and C(-3,-1).

Romashka [77]

In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1

Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle

5 0

3 years ago

you and three friends are going to a restaurant for dinner. you share three appetizers that cost $6 each. you also share two des

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3×6=$18
3×2=$6
total $24/3
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3 years ago

Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12

Montano1993 [528]

$0.05p-0.02(5-2p)=0.05(p-2)-0.12$

$0.05p-0.02(5-2p)=0.05(p-2)-0.12:p$

$
0.05p-0.1+0.04p=0.05p-0.1-0.12
 
$ $|Expand \ the \ equation|$

$0.09p-0.1=0.05p-0.1-0.12
 
$

$0.09p-0.1=0.05p-0.22$

$
0.09p-0.1-0.05p=-0.22
 

$ $|Subtract \ 0.05p \ from \ both \ sides|$

$
0.04p-0.1=-0.22
 
$

$
0.04p=-0.22+0.1
 
$ $|Add \ 0.1 \ to \ both \ sides|$

$
0.04p=-0.12
 
$

$0.04p/0.04=-0.12/0.04
$ $|Divide \ both \ sides \ by \ 0.04|$

$p=-3$

$\star \ Hence \ Solved$

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