Option B) (x + 3)^2 − 5 is the correct answer
Step-by-step explanation:
Given expression is:
![x^2+6x+4](https://tex.z-dn.net/?f=x%5E2%2B6x%2B4)
We will solve eah expression in the options to chek which is equivalent to given expression
So,
<u>A) (x + 3)^2 + 5</u>
![(x + 3)^2 + 5 = x^2+6x+9+5 \\= x^2+6x+14](https://tex.z-dn.net/?f=%28x%20%2B%203%29%5E2%20%2B%205%20%3D%20x%5E2%2B6x%2B9%2B5%20%5C%5C%3D%20x%5E2%2B6x%2B14)
NOT equivalent
<u>B) (x + 3)^2 − 5</u>
![(x + 3)^2 − 5 = x^2+6x+9-5\\= x^2+6x+4](https://tex.z-dn.net/?f=%28x%20%2B%203%29%5E2%20%E2%88%92%205%20%3D%20x%5E2%2B6x%2B9-5%5C%5C%3D%20x%5E2%2B6x%2B4)
Equivalent
Hence,
Option B) (x + 3)^2 − 5 is the correct answer
Keywords: Equivalent expressions, polynomials
Learn more about polynomials at:
#LearnwithBrainly
-72yexponet73 + 2xexponet2 :)
Answer:
80%
Step-by-step explanation:
Answer:
0.9544
Step-by-step explanation:
We are given that mean=18 and standard deviation=1 and we have to find P(16<X<20).
P(16<X<20)=P(z1<Z<z2)
z1=(x1-mean)/standard deviation
z1=(16-18)/1=-2
z2=(x2-mean)/standard deviation
z2=(20-18)/1=2
P(16<X<20)=P(z1<Z<z2)=P(-2<Z<2)
P(16<X<20)=P(-2<Z<0)+P(0<Z<2)
P(16<X<20)=0.4772+0.4772=0.9544
The probability that the height of a tree is between 16 and 20 feet is 95.44%
Given:
The expression is
![\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B3%7D-%5Cdfrac%7B5%7D%7B6%7D-%5Cdfrac%7B2%7D%7B12%7D)
To find:
The expression which is equivalent to the given expression.
Solution:
We have,
![\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B3%7D-%5Cdfrac%7B5%7D%7B6%7D-%5Cdfrac%7B2%7D%7B12%7D)
It can be written as
![=\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{1}{6}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B8%7D%7B3%7D-%5Cdfrac%7B5%7D%7B6%7D-%5Cdfrac%7B1%7D%7B6%7D)
Taking LCM, we get
![=\dfrac{16-5-1}{6}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B16-5-1%7D%7B6%7D)
![=\dfrac{10}{6}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B10%7D%7B6%7D)
![=\dfrac{5}{3}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B5%7D%7B3%7D)
The mixed fraction of this improper fraction is
![=\dfrac{1\times 3+2}{3}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%5Ctimes%203%2B2%7D%7B3%7D)
![=1\dfrac{2}{3}](https://tex.z-dn.net/?f=%3D1%5Cdfrac%7B2%7D%7B3%7D)
So, the expression
is equivalent to the given expression.
Therefore, the correct option is A.