Checking the discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4

Checking the discontinuity at point -2
from the left f(-2) = (-2+2)² = 0
from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2

Checking the discontinuity at point 4
from the left f(4) = -(1/2)*4+1 = -1
from the right f(4) = -1
but there no equality in the equation so,
∴ The function is discontinues at 4

The correct choice is the second
point discontinuity at x = 4 and jump discontinuity at x = -2

5 0

3 years ago

Read 2 more answers

the length of a rectangular sign is 5 times its width. If the sign's perimeter is 24inches, what is the signs area

anastassius [24]

Answer:

20 square inches

Step-by-step explanation:

Set width of sign to x.

Set length of sign to y.

5x=y

2(x+y)=24 inches

2(x+5x)=24 inches

12x=24 inches

width = 2 inches

length = 10 inches

Area = 20 square inches

PLEASE GIVE BRAINLIEST

6 0

3 years ago

In a diagram, X is the midpoint of Segment VZ. VW =5, and VY =20. Find the coordinates of W,X, and Y.

guapka [62]

solution:

$x(a_{x},b_{x})is midpoint of vz\\
a_{x}=\frac{a_{v}+a_{z}}{2}=\frac{-12+22}{2}=\frac{10}{2}=5\\
b_{x}=\frac{b_{v}+b_{z}}{2}=\frac{0+0}{2}=0\\
and,\\
x(5,0)\\
w(a_{w},b_{w}),v_{w} and w is on the right of v.\\
a_{w}-a_{v}=5\\
a_{w}-(-12)=5\\
a_{w}+12=5\\
a_{w}=5-12=-7\\
w(-7,0)\\
y(a_{y},b_{y})=20 and y is on the right of v.\\
a_{y}-a_{v}=20\\
a_{y}-(-12)=20\\
a_{y}+12=20\\
a_{y}=20-12=8\\
y=(8,0)$

7 0

3 years ago

If necessaly, combine like terms. (3x+8)2

mel-nik [20]

Step-by-step explanation:

multiply 2 with the bracket numbers

6x+16=0

6x= - 16

x=-16/6

x= - 8/3

4 0

3 years ago