Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
The all go over 18 so put them all over 18
16/18+12/18+3/18=31/18
31/18 or 1.722222222........
Answer:
10x³ - 13x² + 37x + 8
The answer is B
Step-by-step explanation:
Hope This Helps :)
Plz Mark Brainliest!!!
I believe it is 6 and 36. Not to sure though. So sorry if I'm wrong.
This is the answer to the problem. Hope it helps
