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yaroslaw [1]
4 years ago
5

A grab bag contains 4 football cards and 6 basketball cards. An experiment consists of taking one card out of the bag, replacing

it, and then selecting another card. What is the probability of selecting a football card and then a basketball card? Express your answer as a decimal.
Mathematics
2 answers:
Zinaida [17]4 years ago
5 0
Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6

Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.

Probability of selecting a basketball card = 6/10 = 0.6

Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated. 

Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
Sonja [21]4 years ago
4 0

Answer:

0.24

Step-by-step explanation:

6/10 - baseball cards

4/10 - football cards

6/10 = 0.6

4/10 = 0.4

0.6 X 0.4 = 0.24

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The graph shows how many calories are in different amounts of popcorn. Which of these statements is true?
wlad13 [49]

Answer:

50 calories per cup of popcorn

Step-by-step explanation:

just subtract 25

5 0
3 years ago
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What is the compund interest on 5,000 over 3 years at 5% interest
Katena32 [7]

Answer:

788.13  to the nearest hundredth.

Step-by-step explanation:

Let A be the total amount in the account after 3 years.

The formula is A = P(1 + x/100)^t .

Here P = 5000, x = 5 %  and the time t = 3. years.  

Amount after 3 years = 5000(1 + 5/100)^3

=  5788.13

So the Interest is 5788.13 - 5000

= 788.13.

8 0
3 years ago
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Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
3 years ago
8 + 5 x (11 - 5) - 9<br> Please help me
Natali [406]

I got 60 as my answer

you ALWAYS do your parentheses first

then you do 8+5 and that equals 13•6-9

13 times 6 is 78. then you subtract 9 which will leave you with 60. hope that helped ☺️

7 0
3 years ago
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Adam dropped a rubber ball from a window 40 ft above the sidewalk the ball always bounces half of the height that it drops how f
sergij07 [2.7K]

Answer:

The ball will reach a height of 5 ft by the 4th time.

Step-by-step explanation:

The initial height of the ball is 40 ft, when it bounces from the floor once the height will be 20 ft, the second time it'll be 10 ft, and so on. The sequence that can represent the maximum height of the ball after each bounce is:

{40, 20, 10,...}

This kind of sequence is called a geometric progression, in this kind of progression the next number is related to the one before it by the product of a constant called ratio, in this case 1/2. To calculate a specific position in this sequence we only need the ratio and the first number, using the formula below:

a_n = a*r^(n-1)

Where n is the position we want to know, a is the first number and r is the ratio. In this case we have:

a_4 = 40*(1/2)^(4-1) = 40*(1/2)^3 = 40/8 = 5

The ball will reach a height of 5 ft by the 4th time.

6 0
4 years ago
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