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yaroslaw [1]
4 years ago
5

A grab bag contains 4 football cards and 6 basketball cards. An experiment consists of taking one card out of the bag, replacing

it, and then selecting another card. What is the probability of selecting a football card and then a basketball card? Express your answer as a decimal.
Mathematics
2 answers:
Zinaida [17]4 years ago
5 0
Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6

Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.

Probability of selecting a basketball card = 6/10 = 0.6

Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated. 

Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
Sonja [21]4 years ago
4 0

Answer:

0.24

Step-by-step explanation:

6/10 - baseball cards

4/10 - football cards

6/10 = 0.6

4/10 = 0.4

0.6 X 0.4 = 0.24

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-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{9x}^2\textsf{ - 12x + 4}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{(3x - 2)}^2

Find: \textsf{Simplify the expression}

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<u>Expand</u>

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Therefore, after following the provided information we are able to determine that the expanded form would be 9x^2 - 12x + 4.

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