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baherus [9]
3 years ago
9

Keisha bought N packs of pencils. Each pack has 12 pencils. Write an equation to represent the total number of pencils P that Ke

isha bought.
Mathematics
2 answers:
ruslelena [56]3 years ago
8 0

Answer: Our required expression would be 12N=P

Step-by-step explanation:

Since we have given that

Number of packs of pencils be 'N'.

Number of pencils in each pack = 12

Let the total number of pencils that Keisha bought be 'P'.

According to question, our equation becomes,

12\times N=P\\\\12N=P

Hence, our required expression would be

12N=P

Andrews [41]3 years ago
6 0

Hi!

The equation looks like this:

P = N * 12, where P represents the total number of pencils and N is number of packs

Hope this helps!

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Sedaia [141]

Answer:

The amount of steel used = 94.38 m^{2}

Step-by-step explanation:

Height of the tank = 4.5 m.

Diameter of the tank = 4.2 m.

But,

radius = \frac{diameter}{2}

           = \frac{4.2}{2}

radius  = 2.1 m

Total surface area of a cylinder = 2\pirh + 2\pir^{2}

                                      = 2\pir(r + h)

                                      = 2 x \frac{22}{7} x 2.1 (2.1 + 4.5)

                                      = 44 x 0.3 (6.6)

                                      = 87.12

Total surface area of a cylinder = 87.12 m^{2}

Since \frac{1}{12} of the steel was wasted, then;

\frac{1}{12} x 87.12 = 7.26 m^{2}

Actual area of steel sheet used = 87.12 + 7.26

                                                     = 94.38 m^{2}

Thus, 94.38 m^{2} of steel was used in making the tank.

4 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

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2 years ago
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Neko [114]

Answer:

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Step-by-step explanation:

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Answer:!!

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