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vampirchik [111]
4 years ago
9

$ available at today is worth more than the same amount if received in the future

Business
1 answer:
Kitty [74]4 years ago
3 0

<u>Answer:</u>Money received today can grow at compound rate.

<u>Explanation:</u>

The time value of the money increases based on the interest rates. So dollar earned today has more value than dollar earned tomorrow. The time value of money concept is used in financial decision making. If $1 is received today it can be invested and the rate of interest on that investment is an added value to $1.

Money can earn interest so any amount of money received today is better than receiving the same amount in the future.

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The Board of Governors, the Federal<span> Open Market Committee, and 12 regional </span>reserve<span> banks.</span>
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3 years ago
Which of the following is a reason advertising can be economically wasteful? Advertising provides consumers with price and quali
Hitman42 [59]

Answer:

The correct answer is advertising manipulates the tastes of people and can reduce or decrease the competition.

Explanation:

Advertising is the source through which the company or the firm promote the product or a service of their business, so that the customers could be make aware of the products and the services offered by the firms.

It manipulates the taste of the people by establishing a desire and impedes the competition through increasing the perception of the product differentiation.

4 0
3 years ago
The owner of Genuine Subs, Inc., hopes to expand the present operation by adding one new outlet. She has studied three locations
Gennadij [26K]

Answer:

The selling price per unit (sandwich) is $2.50

The variable cost per unit (sandwich) is $1.80

Contribution margin per unit = Selling price per unit - Variable cost per unit

=$2.50 - $1.80

=$0.70

Target sales volume to achieved at location A

The fixed cost is $5,040 per month

The target profit is $10,500 per month

TargetSales=Fixedcosts+TargetprofitContributionmarginperunitTargetSales=Fixedcosts+TargetprofitContributionmarginperunit

TargetSales=5,040+10,5000.70TargetSales=5,040+10,5000.70

TargetSales=22,200unitsTargetSales=22,200units

The company needs to sell 22,200 units at location A to achieve target profit of $10,500

Target sales volume to achieved at location B

The fixed cost is $5,560 per month

The target profit is $10,500 per month

TargetSales=Fixedcosts+TargetprofitContributionmarginperunitTargetSales=Fixedcosts+TargetprofitContributionmarginperunit

TargetSales=5,560+10,5000.70TargetSales=5,560+10,5000.70

TargetSales=22,943unitsTargetSales=22,943units

The company needs to sell 22,943 units at location B to achieve target profit of $10,500

Target sales volume to achieved at location C

The fixed cost is $5,730 per month

The target profit is $10,500 per month

TargetSales=Fixedcosts+Target

Explanation:

only i can do sorry

6 0
3 years ago
PLZ ANSWER FORST CORRECT ANSWER WILL GET BRAINIEST!!!!!
Ksenya-84 [330]

Answer:

A.

Explanation:

4 0
3 years ago
A rectangular area is to be enclosed and divided into thirds. The family has $400 to spend for the fencing material. The outside
kirill [66]

Answer: The dimensions that will maximize the area enclosed is 100/3 feet sq.

Explanation:

A rectangle has a width and a length.

Taking W as Width and L as Length

Area = W x L

Draw a rectangle and divide it into 2/3 with two lines parallel with the width.

The outside fence perimeter ia given as 2 W + 2 L, while the inside fence length will be 2 W

Therefore, the total cost is gotten as:

[2 W + 2 L] x $10 + 2 W x $20 = $400

Open the bracket,

= 20 W + 20 L + 40 W = $400

= 60 W + 20 L = 400

Make L the subject of formula by dividing both sides by 20,

= 60 W / 20 + 20 L / 20 = 400 / 20

= 3 W + L = 20 ------Equation A

In order to make L the subject of formular still, you will subtract 3 W from both sides of equation A,

3 W + L - 3 W = 20 - 3 W

L = 20 - 3W ----------Equation B

Since Area of a rectangle = W x L, and L = 20 - 3W. Then substitute 20 - 3W as L in the equation below,

= W x ( 20 - 3W )

Open the bracket,

= 20 W - 3 W²

1st derivative:

dA / dW = 20 - 3 x 2 x W

= 20 - 6 W

Assume dA / dW = 0

20 - 6 W = 0

20 - 6 W + 6 W = 0 + 6 W

20 = 6 W

Make W the subject of formula

W = 20/6

We can rewrite it as

W = 2 x 10 / ( 2 x 3 )

So W = 10 / 3

W = 10 / 3 feet

NOTE:

A function has a local maximum or minimum if 1st derivative = 0.

If 2nd derivative < 0 then function has a maximum, but if 2nd derivative > 0 then function has a mimum.

However, 2nd derivative = -6 here, which means function has a maximum.

For W = 10 / 3 feet,

L = 20 - 3W

= 20 - 3 x 10 / 3

= 20 - 10

= 10 feet

The dimensions that will maximize the area enclosed = the Maximum,

It is gotten as:

W x L = 10 / 3 x 10

= 100 / 3 feet sq.

8 0
3 years ago
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