Answer:
B
Step-by-step explanation:
23 can round to 20 and 21 can also round to 20 so all u do is 20x20=400 so 400 is your estimated answer
The question is so dry, mechanical, and devoid of emotion
that it's terrifying.
There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.
-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.
-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient
(10,000,000 events) / (1,560 days)
= 6,410.3 events per day
= 267.1 events per hour
= 4.45 events per minute.
Reciprocally, this is a unit rate of
13.48 seconds per event,
sustained continuously for 4.274 years !
When will we ever learn ! ?
Answer:
.09ft^2
Step-by-step explanation:
The weight in 1980 is
kilograms
<em><u>Solution:</u></em>
From 1980 to 1990, Lior’s weight increased by 25%
His weight is "k" kilograms in 1990
<em><u>To find: weight in 1980</u></em>
This is a percentage increase problem
Let "x" be the weight in kilograms in 1980
<em><u>The percentage increase is given by formula:</u></em>

Here,
Initial value in 1980 = x
Final value in 1990 = k
Percentage increase = 25 %
<em><u>Substituting the values in formula,</u></em>

Thus the weight in kilograms in 1980 is 