Ask question

Ask question

All categories

3 years ago

11

WRITE THE SUM OF THE NUMBERS AS THE PRODUCT OF THEIR GCF AND ANOTHER SUM 40+25

1 answer:

Dennis_Churaev [7]3 years ago

4 0

The greatest common factor (GCF) of 40 and 44 is 4.

Explanation:

44 = 4 x 11

40 = 4 x 10

<em>44 + 40 =</em><span> (4 x 11) plus (4 x10) = </span><em>4 times (11+ 10)</em>

You might be interested in

What is the value of b2 - 4ac for the following equation?<br><br> 2x 2 - 2x - 1 = 0

NikAS [45]

$2x^2-2x-1=0$
$\Delta=b^2-4ac$

$\Delta=(-2)^2-4*2*(-1)=4+8=12$

5 0

3 years ago

Read 2 more answers

(solving rates) At a school camp

masha68 [24]

5 days food for 150 students suggests there was 750 day rations

If there was 100 students this would last 750/100 = 7.5 days.

If it ran out after 4 days there were 750/4 = 187 students (187.5 not valid)

4 0

3 years ago

Circle the volume in cm^3 of a cylinder with the radius 5cm and height 8cm

Phantasy [73]

Answer:

<em>628 </em> $cm^{3}$

Step-by-step explanation:

Since the formula to find the volume of a cylinder is $\pi r^{2}$ h, we just need to fill things in.

Since the radius is 5 and the height is 8 and we know that pi=3.14, our new equation is:

3.14*5^2*8.

5*5=25. Now we simplify.

3.14 * 25 * 8

78.5 * 8

<em>628 </em> $cm^{3}$

Hope this helps!! <3 :)

6 0

3 years ago

Read 2 more answers

Select the reason that best supports statement both 2 and 8 in the given proof.

LenKa [72]

It’s probably 10 given proof

7 0

2 years ago

Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.

Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

$\displaystyle T_ n = ar^{n-1}$

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.

We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

$\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}$

Substitute and simplify:

$\displaystyle 96 = ar^4 \text{ and } 768 = ar^7$

We can rewrite the second equation as:

$\displaystyle 768 = (ar^4) \cdot r^3$

Substitute:

$\displaystyle 768 = (96) r^3$

Hence:

$\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2$

So, the common ratio <em>r</em> is two.

Using the first equation, we can solve for the initial term:

$\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}$

In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.

7 0

2 years ago