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gavmur [86]
3 years ago
12

Find the missing term of the arithmetic sequence 22, ___ , 34, ...

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

28

Step-by-step explanation:

each one is going up by 6

You might be interested in
A. 6<br> b 1/6<br> c 4/16<br> d 1/4
Dmitrij [34]
D. 1/4
Divide 4 and 16 and you will get D
8 0
3 years ago
This Stem-and-Leaf Plot shows the amount of rainfall received in centimeters in each month. What is the median of this data set?
WARRIOR [948]

Answer:

55.5 B

Step-by-step explanation:

We have the following points of data

48, 49, 50, 51, 54, 55, 56, 58, 60, 62, 63, 63

The median is the data point in the middle (when listed in order)

If we find the middle number we'll see that it's between 55 and 56. When this is the case you find the average of  the two numbers (add them and divide by 2)

(55+56)/2=55.5

3 0
3 years ago
Read 2 more answers
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
A and B are two events.
Vesna [10]
In order to determine if the events are independent or not we need to find the conditional probabilities.

The conditional probability of event A, given event B is denoted as P(A|B)

P(A|B)= \frac{P(A*B)}{P(B)}

P(A*B) indicates P(A and B)

Using the values, we get:

P(A|B)= \frac{0.28}{0.8}=0.35

Since P(A|B) is not equal to P(A) this indicates that occurrence of event B has an impact on the occurrence of event A. This shows that the two events are dependent.

Therefore, the correct option is the second one.
2. A and B are not independent events because P(A∣∣B)≠P(A)
5 0
3 years ago
Read 2 more answers
Directions: State whether or not (3, -2) is a solution to the following systems.
andrew11 [14]

(3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17 and (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

<h3>How to determine the whether or not (3, -2) is a solution to the following systems?</h3>

The systems of equations are given as:

1. x - 2y = 7 and 2x + 3y = 0

2. -x - y = -5 and 3x - 4y = 17

3. x + y = 1 and x - y = 6

Next, we substitute (3, -2) for (x, y) in the system of equations.

So, we have:

<u>1. x - 2y = 7 and 2x + 3y = 0</u>

3 - 2 * -2 = 7 and 2 * 3 + 3 * -2 = 0

Evaluate

7 = 7 and 0 = 0

The above equation is true

Hence, (3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0

<u>2.- x - y = -5 and 3x - 4y = 17</u>

-3 + 2 = -5 and 3 * 3 + 4 * 2 = 17

Evaluate

- 1 = - 5 and 1 7 = 1 7

The above equation is false

Hence, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17

<u>3. x + y = 1 and x - y = 6</u>

3 - 2 = 1 and 3 + 2 = 6

Evaluate

1 = 1 and 5 = 6

The above equation is false

Hence, (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

Read more about system of equations at:

brainly.com/question/13729904

#SPJ1

8 0
2 years ago
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