We will draw the graph according to the given
constraints
NOTE: when we draw the graph from
constraints inequalities becomes equalities just
to draw the graph
Given constraints are:
Ar + 34 ≤ 12
20 + 64 <15
Now we draw the graph of given constraints
using graphing calculator. Please see the
attachment for the graph. Shaded region is the
feasible region
The answer is A. Y=2x+2
Because the slope is 2 and it crosses the Y axis at 2
see the attached figure to better understand the problem
Step 
in the triangle ABC
<u>Find the distance AC</u>
we know that
In the right triangle ABC
solve for AC
substitute the values
Step 
in the triangle DEF
<u>Find the distance DF</u>
we know that
In the right triangle DEF
solve for DF
substitute the values
Step 
Find the value of x
we know that
the value of x is the difference between AC and DF
round to the nearest meter-------> 
therefore
<u>the answer is</u>
The value of x is 
For this case we have the following functions:
Equalizing we have:
To solve we factorize, that is, we look for two numbers that when multiplied give a result of 4 and when added together give a result of -4. These numbers are -2 and -2.
Thus, we have:
So, the solution is
Answer:
It depends. Generally no.
Linear equations are generally in the form [math]y=mx+b[/math] and have a domain of [math](-\infty,\infty)[/math], or all real numbers. However, an arithmetic sequence is only defines for the natural numbers (that is, while numbers [math]> 0[/math].
For any two terms in the arithmetic sequence, [math]a_n[/math] and [math]a_{n+1}[/math], there will always be a point on the linear function that lies in between them, and is such not defined in the sequence.
This does not make the sequence and function unrelated, but rather it makes them not the same.
A similar argument applies for geometric sequences and exponential equations.
