sam filled 6 glasses with six glasses with two 2/3 liters of juice in each glass. how many liters of juice did he use ?

1 answer:

6 0

So, Sam filled 6 glasses with 2/3 liters. We want to find out how many liters of juice he used.

To find this out we do 6 * 2/3.
(2/3+2/3+2/3+2/3+2/3+2/3)
(12/3) (Denominator stays the same)
12/3 = 4
Sam uses 4 liters.

Hope this helps you! (:
-Hamilton1757

You might be interested in

Find the slope of the line

dmitriy555 [2]

-5/5 do rise over run

4 0

2 years ago

Please help me it's one question but I have no idea how to do it!

harina [27]

Answer:

roast beef=$6 per sandwich

ham=$5 per sandwich

Step-by-step explanation:

3 0

3 years ago

Simplify the expression -2b - 6 + 3b - 2

Scilla [17]

Hello!

To do this we need to combine like terms, meaning combine the terms that have the same variables.

b is one variable that can be combined:

-2b - 6 + 3b - 2
b - 6 - 2

Now, combine the digits:

b - 8

Hope this helped!

8 0

3 years ago

Evaluate the difference quotient for the given function. Simplify your answer.

nasty-shy [4]

I suppose you mean

$f(x) = \dfrac{x+5}{x+1}$

Then

$f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2$

and the difference quotient is

$\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}$

If it's the case that x ≠ 3, then (x - 3)/(x - 3) reduces to 1, and you would be left with

$\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}$

4 0

2 years ago

Raul calculated that he would spend $125 on school supplies this year but he accually spent 87.50 on school supplies what is his

sergey [27]

Fraction of his error= 87.50/ $125
=0.7
Percentage= 0.7 * 100
= 70%

5 0

3 years ago