Answer: False.
Step-by-step explanation:
There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1
The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.
So the statement is false
Take a pic of whole page so I can see instructions
a. 4 – commutative property
b. 5 – commutative property
c. 0 – identity property
d. 4 – associative property
_____
The commutative property lets you swap the order: (a) + (b) = (b) + (a).
The associative property lets you change the grouping: (a+b)+c = a+(b+c).
The identity property lets you add 0 without changing anything: (a) +0 = (a).
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
45min
Step-by-step explanation:
just mutiply
